A spherical ball has a diameter of 1.00 inch and a mass of 2.00grams. Will the ball float or sink in water? Remember that if the balls's density is greater than 1.00 g?mL (the density of water), the ball will sink.

volume sphere is V = (4/3)*pi*r^3

density = mass/volume

so:

v= 4/3*3.14*0.5^3= 0.52

then take 2.00g/ 0.52 = 3.85g (ball will sink)

To determine if the ball will float or sink in water, we need to compare its density with the density of water. Density is defined as mass per unit volume.

First, let's calculate the volume of the sphere using its diameter. The formula for the volume of a sphere is:

V = (4/3) * π * r^3

Given that the diameter of the ball is 1.00 inch, we can find the radius by dividing the diameter by 2:

r = d/2 = 1.00 inch / 2 = 0.50 inch

Now we can calculate the volume using the formula above:

V = (4/3) * π * (0.50 inch)^3
V = (4/3) * π * 0.125 cubic inches
V ≈ 0.5236 cubic inches

Next, we need to convert the mass of the ball from grams to the appropriate unit for volume, which is milliliters (ml). Since 1 ml is equal to 1 cubic centimeter (cm^3), we can make this conversion:

2.00 grams = 2.00 ml

Now we have the volume and mass of the ball. To calculate its density, divide the mass by the volume:

Density = mass / volume
Density = 2.00 ml / 0.5236 cubic inches
Density ≈ 3.815 g/ml

The ball's density is approximately 3.815 g/ml. Since this density is greater than the density of water, which is 1.00 g/ml, the ball will sink in water.

In conclusion, the ball will sink in water because its density is greater than the density of water.