complete and balance chemical equation for each of the foll

A CH3_CHOH_CH3 --H2SO4-->
B CH3_CHBr_CH3+koH-->

Sure! Let's start with equation A:

CH3_CHOH_CH3 --H2SO4-->

To balance this equation, we need to ensure that the number of atoms on both sides is equal.

First, let's count the number of each type of atom on the left side of the arrow:
C: 4
H: 10
O: 1

Now, let's look at the right side of the arrow (exactly what is being formed is not mentioned, so we'll assume the reaction is forming water):

H2SO4 is sulfuric acid, and when it reacts with an alcohol (CH3CH(OH)CH3), it can function as a dehydrating agent, removing a water molecule (H2O). So the right side of the equation will have the products: CH3CH=CH2 (an alkene) and H2O.

Next, let's count the number of each type of atom on the right side of the arrow:
C: 4
H: 8
O: 1

To balance the equation, we need to have an equal number of each atom on both sides.

Here is the balanced equation for A:
CH3CH(OH)CH3 --H2SO4--> CH3CH=CH2 + H2O

Now let's move on to equation B:

CH3_CHBr_CH3 + KOH -->

For this equation, we need to determine what product is being formed when CH3CHBrCH3 reacts with KOH (potassium hydroxide). In this case, a substitution reaction will occur, where the halogen (bromine, Br) is replaced by the hydroxide ion (OH-).

So the product will be CH3CHOHCH3 (an alcohol) and potassium bromide (KBr).

Now, let's count the number of each type of atom on both sides of the arrow:

On the left side:
C: 4
H: 9
Br: 1

On the right side:
C: 4
H: 10
O: 1
K: 1
Br: 1

To balance the equation, we need to have an equal number of each atom on both sides.

Here is the balanced equation for B:
CH3CHBrCH3 + KOH --> CH3CHOHCH3 + KBr