complete and balance chemical equation for each of the foll
A CH3_CHOH_CH3 --H2SO4-->
B CH3_CHBr_CH3+koH-->
To complete and balance the chemical equations provided, we need to follow a systematic approach. Let's start with equation A:
A: CH3_CHOH_CH3 --H2SO4-->
1. Begin by identifying the reactants and products in the equation. In this case, the reactant is CH3_CHOH_CH3, and the product is not specified.
2. Determine the functional group or components of the reactant that are likely to react with H2SO4. In this case, the hydroxyl (OH) group is a common functional group that can react with H2SO4.
3. Recognize that when the hydroxyl group (OH) reacts with H2SO4, it can undergo an acid-catalyzed dehydration reaction. As a result, water (H2O) is formed as a product.
4. Based on this information, we can now write the balanced chemical equation:
CH3_CHOH_CH3 + H2SO4 -> CH3_CH=C(CH3)2 + H2O
Note that in the final product, the hydroxyl group (-OH) from the reactant has been removed, and a double bond has formed between the carbon atoms.
Moving on to equation B:
B: CH3_CHBr_CH3 + KOH -->
1. Again, begin by identifying the reactants and products in the equation. In this case, the reactant is CH3_CHBr_CH3, and the product is not specified.
2. Recognize that the presence of KOH (potassium hydroxide) suggests a reaction involving a base. In this case, KOH can act as a nucleophile and replace the bromine (Br) atom to form a new compound.
3. Write the balanced chemical equation by replacing the bromine atom with a hydroxyl group (OH):
CH3_CHBr_CH3 + KOH -> CH3_CHOH_CH3 + KBr
Note that in the final product, the bromine atom has been replaced by the hydroxyl group (-OH). Additionally, potassium bromide (KBr) is formed as a byproduct.
Remember, balancing chemical equations involves ensuring that the number of atoms for each element is the same on both the reactant and product sides of the equation. It is important to consider the stoichiometry and valencies of the atoms involved to balance the equation accurately.