A quarterback throws a football at 38 m/s at a certain angle above the horizontal. If it took the ball 6.41 s to reach the top of its path, how long was it in the air?
* I want to say that the formula you use is distance. But im not sure. O r manybe even find out what acceleration was per second.
To find the total time the football was in the air, we need to consider the time it takes for the football to go up to its peak and come back down.
First, let's find the time it takes for the football to reach its peak. We are given that it took 6.41 seconds for the ball to reach the top of its path. This time corresponds to the time it takes for the ball to travel upwards.
The time taken for upward motion is also equal to the time taken for downward motion as the ball follows a symmetrical path. Thus, the total time of flight will be twice the time taken to reach the peak.
So, the total time the ball was in the air is 2 × 6.41 seconds = 12.82 seconds.
Now, let's address your mention of acceleration. In this problem, we are not given any information about the acceleration, but we can assume that the acceleration due to gravity is acting vertically downward throughout the flight of the football. The magnitude of acceleration due to gravity is approximately 9.8 m/s².
Please note that in this particular problem, we are not directly using the formula for distance, but instead using the concept of time of flight and calculating it based on the given information.