A colony of bacteria has a population of ten initially, and doubles in size every three hours. What is the population of the colony after 24 hours of growth ?
2,560
well, it doubles 8 times in 24 hours. So, it has grown by a factor of 2^8
10 * 2^8 = ?
bacteria triples in size every 5 hours. the inital population is 125 cells what will the population be after 15 hours? 25 hours?
To find the population of the bacteria colony after 24 hours, we need to determine how many times the population doubles in 24 hours.
Given that the colony doubles in size every 3 hours, we can calculate the number of doubling periods in 24 hours by dividing 24 by 3:
24 hours ÷ 3 hours/doubling period = 8 doubling periods
Since the population doubles with each period, we can calculate the final population by multiplying the initial population (10) by 2 raised to the power of the number of doubling periods (8):
Final Population = Initial Population × (2^doubling periods)
= 10 × (2^8)
= 10 × 256
= 2560
Therefore, the population of the bacteria colony after 24 hours of growth is 2560.