Out of 300 student in final year in senior secondary school, 200 are offering biology and the150 offering chemistry how many are offering neither biology nor chemistry

Universal set = 300

Biol only = 200 - x
Chem only = 150 - x
Biol nd chem = x
Biol nd chem = 200 - x + x + 150 - x = 300
Biol nd chem = - x + 350 = 300
Collect like terms
Biol nd chem = 350 - 300 = x
X = 50
(Chem U biol)' = chem only + physics only + chem nd physics - universal set
(chem U biol)' = 150 + 50 + 100 - 300
(chem U biol)' = 0
Therefore 0 people are offering neither biology nor chemistry

To find out how many students are offering neither biology nor chemistry, we need to use the concept of set theory and find the number of students who are not in the union of the biology and chemistry sets.

We can start by finding the number of students offering biology and chemistry, which is the intersection of the two sets. Let's call this set "A."

A = 200 (students offering biology) ∩ 150 (students offering chemistry)
A = 50

Next, we can find the number of students offering either biology or chemistry by finding the union of the two sets. Let's call this set "B."

B = 200 (students offering biology) ∪ 150 (students offering chemistry)
B = 200 + 150 - 50 (to remove the intersection)
B = 300

Now, to find the number of students offering neither biology nor chemistry, we subtract the number of students in set B (offering either biology or chemistry) from the total number of students.

Number of students offering neither biology nor chemistry = Total number of students - Number of students offering either biology or chemistry
Number of students offering neither biology nor chemistry = 300 - 300
Number of students offering neither biology nor chemistry = 0

Therefore, there are 0 students offering neither biology nor chemistry out of the 300 students in the final year of senior secondary school.