the volume V of a right circular cone is V=(1/3)π r^2 h. If the height is twice the radius, express the volume V as a function of r.
h=2r? V=2/3 PI r^3
Is there something here that I don't see?
To express the volume V of a right circular cone as a function of r, given that the height is twice the radius, we can start by substituting the value of h in terms of r into the formula.
Given:
Height (h) = 2 * Radius (r)
Substituting h into the original formula, we have:
V = (1/3) * π * r^2 * (2r)
Simplifying the equation:
V = (1/3) * π * 2r * r^2
V = (2/3) * π * r^3
Therefore, the volume V of a right circular cone, when the height is twice the radius, can be expressed as a function of r:
V(r) = (2/3) * π * r^3