Simplify using only positive exponents.
(2r^-1s^2t^0)^-2
----------------
2rs
Thanks in advance!
Working this out:
(2^-2 r^2 s^-4)/ (2 r s) =
r^2/8rs^5
Note: Anything to the 0 power is equal to 1.
I hope this will help.
Sorry but can you help me please I seriously need it.!
how did you get
(2^-2 r^2 s^-4)?
For the numerator (top) we have:
(2 r^-1 s^2 t^0)^-2
Multiply the exponents for each term. For example, (r^-1)^-2 is r^2 --> -1 * -2 = 2
Therefore you have: (2^-2 r^2 s^-4 t^0) or just (2^-2 r^2 s^-4) because t^0 is the same as 1.
I hope this is clearer and will help.
Don't you add the exponents when you are multiplying?
i agree..... anything to the power of 0 is 1
Check your rules for exponents when determining how to treat them.
If you have something like this:
r^2 * r^3 -->with the same base, you add the exponents. This would be r^5 (I'm using * to mean multiply.)
If you have something like this:
(r^2)^3 -->with the same base, you multiply the exponents. This would be r^6 because this is a different rule.
I hope this will be a little clearer.
Oh, thank you!
wait, but then how do you get
r^2/8rs^5 as the answer?
where in the world did the 8 come from?
Check out negative exponents to determine how to treat them. If you have a negative exponent in the numerator (top), flip to the denominator (bottom) and make the exponent positive. If you have a negative exponent in the denominator, flip to the numerator and make the exponent positive.
We had this:
(2^-2 r^2 s^-4)/ (2 r s)
Flip the negative exponents (with their respective bases) to the denominator and make them positive.
I'll show you what I mean:
r^2 / (2^2 s^4 2 r s) -->flipping 2^-2 to the denominator and making the exponent positive AND flipping s^-4 to the denominator and making the exponent positive. (Note: 2^2 = 4)
Simplifying:
r^2 / (4 s^4 2 r s) -->multiply 4 * 2 to get 8; add exponents with the same bases. s^4 * s gives us s^5
We end up with:
r^2 / 8rs^5
I hope this helps.
Wow, thanks!