Joe Smith, the chemical engineer from Acme Chemical Company, wanted to determine the final volume in a large glass cylinder is he dropped a 12.52 pound ingot of lead whose density was 11.3 g/cm^3 into the cylinder which already contained 2500. mL of water. What is the final volume of water in the cylinder.
12.52 lbs = 5.68 kg = 5680 grams
well first of all the volume of water does not change. The same water is still there unless it splashed out.
However the final volume of stuff in the cylinder increases by
the volume of lead which is
5680 grams (1 cm^3/11.3 grams)
= 503 cm^3 = 503 mL
so what they want is probably
503 + 2500 mL