Vehicle A is traveling at 93.602fps and is 819.017 feet behind vehicle B. Vehicle A takes 8.75 seconds to overtake vehicle B. How fast is vehicle B traveling?

the difference in speeds is

819.017ft/8.5s = 96.355ft/s

so, what's wrong with this problem?

speed does not match the distance, let me rethink....

I'm not getting it, can it not be solved with info given. The difference between the two speeds is .247. .247*60*60/5280 = 0.16mph. vehicle per near stopped.

To find the speed of vehicle B, we can use the formula:

Speed = Distance / Time

We already know the speed of vehicle A, which is 93.602 feet per second (fps), and we know the time it takes for vehicle A to overtake vehicle B, which is 8.75 seconds. We need to find the distance between the two vehicles in order to calculate the speed of vehicle B.

The distance between the two vehicles can be calculated by multiplying the speed of vehicle A by the time it takes to overtake vehicle B:

Distance = Speed * Time

Distance = 93.602 fps * 8.75 seconds
Distance = 818.9135 feet

Now that we have the distance between the two vehicles, which is approximately 818.9135 feet, we can find the speed of vehicle B.

Speed of B = Distance / Time

Speed of B = 818.9135 feet / 8.75 seconds
Speed of B ≈ 93.6035 fps

Therefore, vehicle B is traveling at approximately 93.6035 feet per second (fps).