A bullet is fired horizontally with a velocity of 40m/m from the top of a building 50m height.How far from the foot of the building will the bullet be assumed to touch the ground?

Please solve for me the question above.

how long to fall from 50 m?

h = (1/2) g t^2
t = sqrt (2 h/g) = srt (100/9.81)
= 3.19 seconds

d = u t = 40 * 3.19

No

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Study

To determine the horizontal distance the bullet will travel before hitting the ground, we can use the principles of projectile motion. Here's how you can calculate it:

1. First, we need to find the time it takes for the bullet to hit the ground. We can use the equation for vertical displacement in free fall:

y = ut + (1/2)gt²

In this equation, y represents the vertical displacement (50m), u represents the initial vertical velocity (0 m/s since the bullet is fired horizontally), g represents the acceleration due to gravity (-9.8 m/s²), and t represents the time.

Plugging in the values, the equation becomes:

50 = (0)t + (1/2)(-9.8)t²

Simplifying the equation further, we get:

4.9t² = 50

Divide both sides by 4.9 to solve for t:

t² = 10
t = √10 ≈ 3.16 seconds (taking the positive square root since time cannot be negative)

So, the bullet takes approximately 3.16 seconds to hit the ground.

2. Now, we can find the horizontal distance traveled by the bullet. We can use the equation for horizontal distance:

x = ut

In this equation, x represents the horizontal distance, u represents the initial horizontal velocity (40 m/s), and t represents the time.

Plugging in the values, the equation becomes:

x = (40)(3.16)
x ≈ 126.4 meters

Therefore, the bullet will hit the ground approximately 126.4 meters from the foot of the building.