A piece of copper ball of mass 20 gram at 200 degree celcius is place in a copper calorimeter of mass 60 gram containing 50 grm of water at 30 degree celcius, ignoring heat loses calculate the final steady temperature of the mixture. ( S. H. C of water is 4200j/kgk )

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  1. .020 Cc (200 - T) = (.060 Cc + .050*4200) (T-30)
    where Cc is specific heat of copper in J/kg deg C

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  2. help me solve the question above

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  3. A piece of copper ball of mass 20gram at 200degrees Celsius is placed in the copper calorimeter of mass 60gram containing 50gram of water at 30degrees Celsius ignoring it losses calculated the final stages of temperature. take it specific heat capacity of water 4200Jkg k, specific heat capacity of copper is 400Jkgk

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  4. Good for research please help me solve the above problem

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