How many tiles of length 8cm breath 5cm are needed to tile a floor of dining space which is 400 cm long and 300 cm wide

If we lay the tiles so the the length of the tile falls along the 4 m floor length, then we need 400/8 or 50 tiles along the length, and 300/5 or 60 tiles along the width.

Which is 50x60 or 3000 tiles, just like anjali had

but if we lay the width along the 400 cm length, we will need
400/5 or 80 tiles along that way, and
300/8 or 37.5 rows of tiles the other way.
Which means we have to cut some tiles
and we will need 80x38 or 3040 tiles.

To calculate the number of tiles needed to tile the dining space, you need to determine the area of the floor and the area covered by each tile.

1. Calculate the area of the dining space:
The area of the floor is given by the length multiplied by the width:
Area = Length × Width
Area = 400 cm × 300 cm
Area = 120,000 square cm

2. Calculate the area covered by each tile:
The area covered by each tile is given by the length multiplied by the width of each tile:
Area per tile = Length of tile × Width of tile
Area per tile = 8 cm × 5 cm
Area per tile = 40 square cm

3. Determine the number of tiles needed:
Divide the total area of the floor by the area covered by each tile:
Number of tiles needed = Area of the floor ÷ Area per tile
Number of tiles needed = 120,000 square cm ÷ 40 square cm
Number of tiles needed = 3,000 tiles

Therefore, you would need 3,000 tiles of length 8cm and breadth 5cm to tile the dining space.

length of floor of dining space=400cm

breadth=300cm
area=400×300
=120000cm^2
length of tile=8cm
breadth=5cm
area of one tile =8×5
=40cm^2
tiles required =120000/40
=3000 tiles