A solution of thiosulfate ions has been prepared by dissolving 4.5g of Na2S2O3.5H2O in 250 ml of solution.
Calculate the concentration of the thiosulfate ions S2O3^2- in the solution
Well, if I were to calculate the concentration of the thiosulfate ions in the solution, I would need to know the molar mass of Na2S2O3.5H2O. I'll assume you know that it's approximately 248.2 g/mol.
So, first, we need to convert the mass of Na2S2O3.5H2O to moles. We can do this by dividing the mass (4.5g) by the molar mass (248.2 g/mol). This gives us approximately 0.018 mole.
Next, we need to convert the volume of the solution (250 ml) to liters. There are 1000 ml in 1 liter, so the volume is 0.25 liters.
Now, we can calculate the concentration (C) of the thiosulfate ions S2O3^2- by dividing the moles of S2O3^2- (0.018 mole) by the volume of the solution in liters (0.25 liters). This gives us approximately 0.072 M.
Therefore, the concentration of the thiosulfate ions S2O3^2- in the solution is approximately 0.072 M.
But hey, why did the scarecrow become a chemist? Because he always had some corn-versions to make!
To calculate the concentration of thiosulfate ions in the solution, we first need to convert the mass of Na2S2O3·5H2O to moles.
The molar mass of Na2S2O3·5H2O can be calculated by adding the atomic masses of its constituent elements:
Na (sodium) - 22.99 g/mol
S (sulfur) - 32.07 g/mol
O (oxygen) - 16.00 g/mol
H (hydrogen) - 1.01 g/mol
O (oxygen) - 16.00 g/mol
To calculate the molar mass of Na2S2O3·5H2O, we have:
(2 * Na) + S + (3 * O) + (5 * (H + O))
= (2 * 22.99) + 32.07 + (3 * 16.00) + (5 * (1.01 + 16.00))
= 45.98 + 32.07 + 48.00 + 85.05
= 211.10 g/mol
Now, let's calculate the moles of Na2S2O3·5H2O:
moles = mass / molar mass
= 4.5 g / 211.10 g/mol
≈ 0.02136 mol
Next, we need to calculate the concentration of thiosulfate ions (S2O3^2-) in the solution.
The concentration is defined as the number of moles of solute divided by the volume of the solution.
First, we need to convert the volume of the solution from milliliters (ml) to liters (L):
volume (L) = volume (ml) / 1000
= 250 ml / 1000
= 0.25 L
Now we can calculate the concentration:
concentration (mol/L) = moles / volume (L)
= 0.02136 mol / 0.25 L
= 0.08544 mol/L
Therefore, the concentration of thiosulfate ions (S2O3^2-) in the solution is approximately 0.08544 mol/L.
To calculate the concentration of thiosulfate ions (S2O3^2-) in the solution, we need to convert the mass of Na2S2O3.5H2O to moles and then divide by the volume of the solution.
Step 1: Convert the mass of Na2S2O3.5H2O to moles.
The molar mass of Na2S2O3.5H2O can be calculated by adding the atomic masses of each element present in the compound.
Na (sodium) = 22.99 g/mol
S (sulfur) = 32.07 g/mol
O (oxygen) = 16.00 g/mol
H (hydrogen) = 1.01 g/mol
Na2S2O3.5H2O = (2 * Na) + (2 * S) + (3 * O) + (5 * H) + (10 * O)
= (2 * 22.99) + (2 * 32.07) + (3 * 16.00) + (5 * 1.01) + (10 * 16.00)
= 45.98 + 64.14 + 48.00 + 5.05 + 160.00
= 323.17 g/mol
Next, we can calculate the number of moles of Na2S2O3.5H2O using the given mass:
moles = mass / molar mass
moles = 4.5 g / 323.17 g/mol
moles = 0.01394 mol
Step 2: Calculate the concentration.
Concentration is defined as the amount of solute (moles) divided by the volume of solution (in liters).
Given:
The volume of the solution = 250 ml = 0.250 L
Concentration (C) = moles / volume
C = 0.01394 mol / 0.250 L
C = 0.05576 mol/L
Therefore, the concentration of thiosulfate ions (S2O3^2-) in the solution is 0.05576 mol/L.
mols Na2S2O3.5H2O = grams/molar mass = ?
Then M = mols/L.