if the area of parallelogram is 192cm² and the altitude is three times the corresponding base then what is length of base and altitude
let base of parallelogram =a
then altitude will be=3a
area of parallelogram=base × altitude
=a× 3a
192=3a^2
192/3=a^2
64=a^2
8=a
so,base=8cm
altitude=8×3
=24cm
To find the length of the base and altitude of the parallelogram, we can use the formula for calculating the area of a parallelogram:
Area = base x altitude
Given that the area of the parallelogram is 192 cm² and the altitude is three times the corresponding base, we can write the following equation:
192 = base x (3 * base)
Rearranging the equation:
192 = 3 * base²
Dividing both sides by 3:
base² = 64
Taking the square root of both sides:
base = √64
base = 8 cm
Since the altitude is three times the corresponding base:
altitude = 3 * base
altitude = 3 * 8
altitude = 24 cm
Therefore, the length of the base is 8 cm and the altitude is 24 cm.