A line has a slope of
1/2 and passes through the point (0,5). What is the equation of the line?
A) y = 1/2x + 5
B) y = 1/2x - 5
C) y = 5x + 1/2
D) y = -5x + 1/2
How do i figure this out?
is it D?
y = (1/2) x + b
5 = (1/2) 0 + b
b = 5
so
y = (1/2) x + 5
which I guess you mean for A)
but what you typed was
y = 2/(2x) + 5
Thank you, I'm so not good at this.
y= mx + b
(1/2) is the slope.
m in the equation is the slope
(0,5)
x= 0
y or b= 0
y=1/2x + 5
To figure out the equation of a line with a given slope and a given point, you can use the point-slope formula.
The formula for a line in point-slope form is:
y - y1 = m(x - x1)
In this formula, (x1, y1) is the given point on the line, and m is the slope.
In this case, the given slope is 1/2 and the given point is (0, 5). Plugging these values into the formula, we get:
y - 5 = (1/2)(x - 0)
Simplifying, we have:
y - 5 = (1/2)x
To get the equation in slope-intercept form (y = mx + b), where b is the y-intercept, we can solve for y by adding 5 to both sides:
y - 5 + 5 = (1/2)x + 5
y = (1/2)x + 5
So the equation of the line with a slope of 1/2 passing through the point (0, 5) is y = (1/2)x + 5.
Comparing this equation with the given options, we see that the correct answer is A) y = (1/2)x + 5.