A 10 ohms, 8 ohms, and 5 ohms resistor connected in series to a Volts source. Find the current in each resistor.
If in SERIES the SAME CURRENT passes through all three and the voltages add up to the battery voltage.
10 i + 8 i + 5 i = V
or
23 i = V
i = V/23
To find the current flowing through each resistor, we need to apply Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R), represented by the formula I = V/R.
In this case, the resistors are connected in series, which means that the same current flows through each resistor.
First, we need to find the total resistance (RT) in the circuit by summing up the resistances of the individual resistors. So, RT = 10 ohms + 8 ohms + 5 ohms = 23 ohms.
Next, we need to determine the potential difference or voltage (V) across the series combination of resistors. This depends on the value of the voltage source connected. Let's say the source provides a voltage of V volts.
Now, we can calculate the current flowing through each resistor using Ohm's Law. The current through each resistor is the voltage across the resistors divided by their respective resistance.
For the 10 ohms resistor, the current (I1) is given by I1 = V/10.
For the 8 ohms resistor, the current (I2) is given by I2 = V/8.
For the 5 ohms resistor, the current (I3) is given by I3 = V/5.
By substituting the value of V, you will be able to calculate the currents flowing through each resistor.