Find the percent by mass of sodium chloride in a 1.15M NaCl solution. The density of the solution is 1.07g/mL.
Why did the sodium chloride go to therapy? It just couldn't find its balance!
But in all seriousness, to find the percent by mass of sodium chloride in a 1.15M NaCl solution, we need to calculate the mass of NaCl present in 1 liter of the solution.
First, let's determine the mass of 1 liter (1000 mL) of the solution. Given that the density is 1.07g/mL, the mass of 1000 mL (1L) of the solution is:
1000 mL x 1.07 g/mL = 1070 grams.
Since the solution is 1.15M NaCl, this means there are 1.15 moles of NaCl in 1 liter of the solution. To calculate the mass of 1.15 moles of NaCl, we need to use the molar mass of NaCl, which is 58.44 g/mol.
Mass of 1.15 moles of NaCl = 1.15 mol x 58.44 g/mol = 67.186 grams.
Now, we can calculate the percent by mass of NaCl in the solution:
(67.186 g NaCl / 1070 g solution) x 100% = 6.28%.
So, the percent by mass of sodium chloride in a 1.15M NaCl solution with a density of 1.07g/mL is approximately 6.28%.
To find the percent by mass of sodium chloride in the solution, we can use the equation:
Percent by mass = (Mass of solute / Mass of solution) x 100
First, we need to calculate the mass of NaCl in the solution.
Step 1: Calculate the volume of the solution
The density of the solution is given as 1.07 g/mL. Since the density is provided in grams per milliliter, the mass of the solution is equal to the volume of the solution in milliliters. Therefore, the volume of the solution is:
Volume of solution = 1.15 L x 1000 mL/L = 1150 mL
Step 2: Calculate the mass of NaCl
The molarity of the solution, 1.15M, represents 1.15 moles of NaCl per 1 liter of solution. Therefore, we can convert the moles of NaCl to grams using its molar mass.
Molar mass of NaCl = 22.99 g/mol for sodium + 35.45 g/mol for chlorine = 58.44 g/mol
Mass of NaCl = 1.15 mol x 58.44 g/mol = 67.23 g
Step 3: Calculate the percent by mass
Now, we can calculate the percent by mass using the equation mentioned earlier:
Percent by mass = (67.23 g / 1150 mL) x 100
To complete the calculation, we need to convert milliliters to grams since the density is given in grams per milliliter:
Mass of solution = 1150 mL x 1.07 g/mL = 1230.5 g
Percent by mass = (67.23 g / 1230.5 g) x 100
Percent by mass = 5.46%
Therefore, the percent by mass of NaCl in the 1.15M NaCl solution is approximately 5.46%.
To find the percent by mass of sodium chloride in a solution, we need to determine the mass of sodium chloride present in a given mass of the solution.
First, we need to calculate the mass of the NaCl in the solution. We know the molarity (M) of the solution, which is 1.15M. Molarity is defined as the number of moles of solute per liter of solution.
So, to find the moles of NaCl in the solution, we multiply the molarity by the volume of the solution. The volume of the solution can be determined using its density.
The density of the solution is given as 1.07 g/mL. We need to convert the density to grams per liter (g/L) since the molarity is given as moles per liter.
To convert grams per milliliter to grams per liter, we multiply by 1000:
Density (g/L) = Density (g/mL) × 1000
Density (g/L) = 1.07 g/mL × 1000 = 1070 g/L
Now we can determine the volume of the solution. We have the molarity, which is 1.15M, and the volume.
Molarity (M) = Moles of solute (NaCl) / Volume of solution (L)
We can rearrange the equation to solve for the volume of the solution:
Volume of solution (L) = Moles of solute (NaCl) / Molarity (M)
Given that the molarity is 1.15M, we can plug it into the equation:
Volume of solution (L) = Moles of solute (NaCl) / 1.15M
Next, we need to determine the moles of solute (NaCl) in the solution. We can do this by rearranging the molarity equation:
Moles of solute (NaCl) = Molarity (M) × Volume of solution (L)
Substituting the known values:
Moles of solute (NaCl) = 1.15M × Volume of solution (L)
Finally, multiplying the moles of solute by the molar mass of NaCl gives us the mass of NaCl present in the solution.
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Mass of NaCl (g) = Moles of solute (NaCl) × Molar mass of NaCl
Substituting the known values:
Mass of NaCl (g) = (1.15M × Volume of solution (L)) × 58.44 g/mol
Now, to calculate the percent by mass of sodium chloride in the 1.15M NaCl solution, we divide the mass of NaCl by the total mass of the solution and multiply by 100.
Percent by mass of NaCl = (Mass of NaCl (g) / Total mass of the solution) × 100
Total mass of the solution can be calculated by multiplying the volume of the solution (in liters) by the density (in grams per liter).
Total mass of solution (g) = Volume of solution (L) × Density (g/L)
Substituting the known values:
Total mass of solution (g) = Volume of solution (L) × 1070 g/L
Now, we have all the required values to calculate the percent by mass of sodium chloride in the 1.15M NaCl solution:
Percent by mass of NaCl = (Mass of NaCl (g) / Total mass of solution (g)) × 100
By plugging in the calculated values for the mass of NaCl and the total mass of the solution, we can solve for the percent by mass of sodium chloride.
1.15 M NaCl = 1.15 mols/L of solution.
How many grams is 1.15 mols? That will be 1.15 mols x molar mass NaCl = approximately 67.3 g/L.
How much does the L of solution weigh? It will weigh (has a mass of) 1.07 g/mL x 1000 mL = 1070 g.
So our solution is 67.3 g NaCl/1070 g soln = approximately 0.063 g NaCl/g soln. Multiply that by 100 to obtain the g/100 which is the percent or approximately 6.3%. You need to check my work carefully and do the math better. I just estimated. Also watch the number of significant figures if your prof is picky about that.