A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. What horizontal force must be applied to the box for it to start sliding along the surface?
Calculate the maximum static frictional force a wooden block of 600g experiences when it: (1)rests on a horizontal plane , subject to an applied force , with a coefficient of friction of 0,5?
.3 * 55 * 9.81
ok is this the problem needed to solve this? and if so its the answer 161.7?
To determine the horizontal force required to start the box sliding, we need to consider the force of static friction. The formula for static friction can be written as:
Fs = μs * N
where Fs is the force of static friction, μs is the coefficient of static friction, and N is the normal force.
Before calculating the force of static friction, we need to find the normal force acting on the box. When an object is resting on a horizontal surface, the normal force is equal to the weight of the object, which can be calculated as:
N = m * g
where N is the normal force, m is the mass of the box, and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Substituting the given values, we have:
N = 55.0 kg * 9.8 m/s^2
N = 539 N
Now that we know the normal force, we can calculate the force of static friction:
Fs = μs * N
Fs = 0.300 * 539 N
Fs = 161.7 N
Therefore, a horizontal force of 161.7 N must be applied to the box to start it sliding along the surface.