75% of the students in a class passed an exam if 2 more students had passed the exam , 80% would have been successful . how many students are there in the class.
75/100x+2=80/100x
3/4x+2=4/5x
2=4/5x-3/4x
Now take LCM of 5 and 4
2 =16x-15x/20
2=x/20
Now divide two by one and x by twenty then multiply both
X=2×20=40 students
40
can i see my test
75/100*x+2=80/100*x
To find the number of students in the class, we can use algebraic equations. Let's say the total number of students in the class is 'x'.
According to the problem, 75% of the students in the class passed the exam. So, the number of students who passed the exam is 0.75x.
If 2 more students had passed the exam, the total number of students who passed the exam would have been 0.75x + 2.
According to the problem, if 2 more students had passed the exam, 80% of the students in the class would have passed the exam. So, the equation becomes:
0.8x = 0.75x + 2
To solve this equation and find the value of 'x', subtract 0.75x from both sides:
0.8x - 0.75x = 2
0.05x = 2
Now, divide both sides by 0.05:
x = 2 / 0.05
x = 40
Therefore, there are 40 students in the class.
.75x + 2 = .80x
Now you can find x