In right triangle ABC,BC=8cm and AC=17cm.Find the value of sin C
8/17
well, AB=15, so draw the triangle and it will be clear.
To find the value of sin C in a right triangle ABC, we need to use the relationship between the sides of a right triangle and trigonometric ratios. In this case, we are given the lengths of the sides BC and AC.
Since AC is the hypotenuse of the right triangle, we can use the sine ratio:
sin C = BC / AC
Plugging in the given values, we have:
sin C = 8cm / 17cm
Now, we can simplify this ratio:
sin C = 8/17
Therefore, the value of sin C in the right triangle ABC is 8/17.
To find the value of sin C in a right triangle ABC, we first need to identify which angle C corresponds to in the triangle.
In a right triangle, one angle is always 90 degrees, which is referred to as a right angle. The other two angles are acute angles (less than 90 degrees).
Based on the information given, we can determine that angle C is the angle opposite to the side with length BC, since angle C is neither a right angle nor the angle opposite to the hypotenuse.
Now, to find sin C, we can use the relationship between the sides of a right triangle and the sine function: sin C = (opposite side) / (hypotenuse).
In this case, the opposite side is BC, which has a length of 8 cm, and the hypotenuse is AC, which has a length of 17 cm.
So, sin C = BC / AC = 8 cm / 17 cm = 0.4706 (rounded to four decimal places).
Therefore, the value of sin C in the right triangle ABC is approximately 0.4706.