Sarah walks 300 m North ,50 m East and then she walks 300 m South. What is the displacement? Thanks in advance too!!
300(N) + 300(s) + 50(E)
D = 300(N) - 300(N) + 50(E)
D = 50m(E)
Thank you!!!
To find the displacement, we need to consider the total vector sum of Sarah's movements.
First, let's represent the North direction as positive and the South direction as negative. Sarah walks 300 m North and then walks 300 m South, so the total displacement in the vertical direction is 300 m - 300 m = 0 m.
Next, let's represent the East direction as positive. Sarah walks 50 m East. Since there is no equivalent West movement mentioned, we can assume that her displacement in the horizontal direction is 50 m.
Now, to find the overall displacement, we need to use vector addition. We can use the Pythagorean theorem to find the magnitude of the displacement and trigonometry to find the direction.
The magnitude of the displacement can be calculated using the formula: magnitude = √(vertical displacement^2 + horizontal displacement^2).
In this case, magnitude = √(0^2 + 50^2) = √2500 = 50√2 ≈ 70.714 m (rounded to three decimal places).
To find the direction of the displacement, we can use the inverse tangent function: angle = arctan(vertical displacement / horizontal displacement).
In this case, angle = arctan(0 / 50) = arctan(0) = 0 degrees.
Therefore, the displacement is approximately 70.714 m in the East direction (0 degrees).