A 50 ml sample of calcium hydroxide solution required 19.50 ml of 0.1050N HCL titration. Calculate the amount of calcium hydroxide in the 50 sample?
0.1515 grams
To calculate the amount of calcium hydroxide in the 50 ml sample, we first need to determine the number of moles of HCl used in the titration. Then, we can use the balanced equation between HCl and calcium hydroxide to find the number of moles of calcium hydroxide present.
1. Calculate the number of moles of HCl used:
We have the volume and concentration of HCl used in the titration.
Moles of HCl = Volume of HCl (L) × Concentration of HCl (mol/L)
Moles of HCl = 0.01950 L × 0.1050 mol/L
2. Use the balanced equation to determine the moles of calcium hydroxide:
The balanced equation for the reaction between HCl and calcium hydroxide is:
Ca(OH)2 + 2HCl → CaCl2 + 2H2O
From the equation, we can see that the ratio of HCl to calcium hydroxide is 2:1.
Therefore, moles of calcium hydroxide = 1/2 × Moles of HCl
3. Calculate the amount of calcium hydroxide:
Now, we can find the amount of calcium hydroxide in grams using the molar mass of Ca(OH)2.
Amount of Ca(OH)2 (g) = Moles of Ca(OH)2 × Molar mass of Ca(OH)2
Make sure to look up the molar mass of Ca(OH)2 in the periodic table to complete the calculation.
To calculate the amount of calcium hydroxide in the 50 ml sample, we can use the concept of stoichiometry and the equation balanced equation for the reaction between calcium hydroxide (Ca(OH)2) and hydrochloric acid (HCl):
Ca(OH)2 + 2HCl → CaCl2 + 2H2O
From the balanced equation, we can see that 1 mole of calcium hydroxide reacts with 2 moles of hydrochloric acid.
First, let's calculate the number of moles of hydrochloric acid (HCl) used in the titration:
Moles of HCl = Volume (in liters) x Concentration (in moles per liter)
= 0.01950 L x 0.1050 mol/L
= 0.0020475 moles
Since the reaction is 1:2 between calcium hydroxide and hydrochloric acid, the number of moles of calcium hydroxide (Ca(OH)2) will be half the number of moles of HCl:
Moles of Ca(OH)2 = 0.0020475 moles / 2
= 0.00102375 moles
Now, we can calculate the amount of calcium hydroxide in the 50 ml sample.
Amount of Ca(OH)2 = Moles x Molar Mass
= 0.00102375 moles x (40.08 g/mol) (the molar mass of Ca(OH)2)
= 0.04099 g
Therefore, the amount of calcium hydroxide in the 50 ml sample is 0.04099 grams.