Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.
(-8, 0) and (1, 5)
I am struggling too
(x1, y1) = (-8, 0)
(x2, y2) = (1, 5)
m= y2 - y1/ x2 - x1
m = 5 - 0 / 1 -(-8)
m = 5 / 9
y - y1 = m(x - x1)
y - 0 = 5/9(x - (-8))
y = 5/9(x + 8)
9y = 5(x + 8) is your final answer
(5-0) / (1+8) = (y-5)/(x-1)
plug and chug
Write the standard form of the line that passes through the point (1, 5) and is parallel to the x-axis. Include your work in your final answer.
To find the standard form of the line that passes through the given points (-8, 0) and (1, 5), we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
where (x1, y1) is one of the given points and m is the slope of the line.
First, let's calculate the slope (m) using the formula:
m = (y2 - y1)/(x2 - x1)
Substituting the values of the given points into the formula:
m = (5 - 0)/(1 - (-8))
= 5/9
So the slope of the line passing through the given points is 5/9.
Now, let's choose one of the given points, say (-8, 0), and substitute the values of x1, y1, and m into the point-slope form:
y - 0 = (5/9)(x - (-8))
Simplifying the equation:
y = (5/9)(x + 8)
Now, let's convert this equation into the standard form Ax + By = C, where A, B, and C are integers and A is positive:
Multiply both sides by 9 to clear the fraction:
9y = 5(x + 8)
Distribute the 5:
9y = 5x + 40
Reorder the terms:
5x - 9y = -40
Therefore, the standard form of the line that passes through the points (-8, 0) and (1, 5) is 5x - 9y = -40.