A Shopkeeper sold a total of 15 boxes of pencils on Monday and Tuesday. He sold 3 more boxes on Monday than on Tuesday. There were 12 pencils in each box. How many pencils did he sell on Monday?
Let x = the number of boxes sold on Monday.
x + x - 3 = 15
2x = 18
x = 9
9 * 12 = ?
To find out how many pencils the shopkeeper sold on Monday, we can start by assigning variables to the information given:
Let's say the number of boxes sold on Monday is M.
Let's say the number of boxes sold on Tuesday is T.
According to the given information, the following equations can be set up:
M + T = 15 (The total number of boxes sold on Monday and Tuesday is 15)
M = T + 3 (He sold 3 more boxes on Monday than on Tuesday)
To solve for the value of M, we need to substitute the second equation into the first equation by replacing M with T + 3:
(T + 3) + T = 15
Now we can solve for T:
2T + 3 = 15
2T = 15 - 3
2T = 12
T = 12/2
T = 6
So, the shopkeeper sold 6 boxes of pencils on Tuesday.
To find the number of pencils sold on Monday, we can substitute T = 6 into our second equation:
M = 6 + 3
M = 9
Therefore, the shopkeeper sold 9 boxes of pencils on Monday.
Since each box contains 12 pencils, the number of pencils sold on Monday would be:
9 boxes * 12 pencils/box = 108 pencils.