need an equation in slope intercept form when I know (-6,1) (-3,2)
(-6,1), (-3,2).
m = (2-1)/(-3-(-6))/ = 1/3.
Y = mx + b.
(1/3)(-6) + b = 1.
-2 + b = 1.
b = 3.
Y = (1/3)x + 3.
m = (2-1)/(-3-(-6))/ = 1/3.
Y = mx + b.
(1/3)(-6) + b = 1.
-2 + b = 1.
b = 3.
Y = (1/3)x + 3.