Mr.Jackson is preparing bags of treats to give trick or treaters on Halloween. He has 48 pieces of candy and 60 pieces of gum.He uses all the candy and gum, and he puts the same ratio of candy to gum in each bag. What is the largest number of bags he could have made.

48/60 = 4/5

48/4 = ?
60/5 = ?

12 bags

To find the largest number of bags that Mr. Jackson can make with the given candy and gum, we need to determine the greatest common divisor (GCD) of the two numbers: 48 and 60.

Step 1: Find the prime factorization of both 48 and 60.
- Prime factorization of 48: 2 × 2 × 2 × 2 × 3
- Prime factorization of 60: 2 × 2 × 3 × 5

Step 2: Identify the common prime factors.
- Common prime factors: 2 × 2 × 3 = 12

Step 3: Multiply the common prime factors to find the GCD.
- GCD(48, 60) = 12

Therefore, the largest number of bags Mr. Jackson could have made is 12.