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Create an image of two beautifully designed spinners placed side by side. Each spinner should be divided evenly into four sectors, labeled with the numbers from one to four. Position the pointers in a manner they seem to have recently spun and came to rest; the one on the left in sector two, and the one on the right in sector one. Ensure the spinners are colored differently to highlight their individuality yet their shared purpose. Pay heed to aesthetics and use a minimalist approach to the design, omitting any textual reference or figures for a clean and focused illustration

Each spinner is divided into four equal sectors (1-4). The pointer in each spinner, when spun, is equally likely to rest in any one of the four sectors. The pointer in each spinner is spun once. What is the probability that the sum of both scores is less than five

Make a table for the two spins

X| 1 2 3 4
---------
1| 2 3 4 5
2| 3 4 5 6
3| 4 5 6 7
4| 5 6 7 8
Out of the 16 possible outcomes, count how many satisfy the given condition, and divide this number by the number of possible outcomes.

3/8

Each spinner is divided into 5 equal sectors. (Two separate spinners) The pointer in each spinner, when spun, is equally likely to rest in any one of the 5 sectors. The pointer in each spinner is spun once. List the sample space and find the probability that the sum of both scores is:

a) odd
b) Even
c) At least 7
d) Less than 7

A.fair.six-side.die.is.throw.find.the.prob.of.get.the.follw.(a)a3.(b)a4.(c)a9.(d)a1.or.a2

Well, let's dive into the world of spinners and probability!

For the first spinner, since each sector is equally likely, the probability of the pointer landing on any specific sector is 1/4 for each sector.

Now, let's move on to the second spinner. Just like the first one, the probability of the pointer landing on any given sector is also 1/4 for each sector.

To find the probability that the sum of both scores is less than five, we need to consider all the possible outcomes that satisfy this condition.

Let's take a look at all the possible combinations of outcomes:

1st spinner - Sector 1 & 2nd spinner - Sector 1
1st spinner - Sector 1 & 2nd spinner - Sector 2
1st spinner - Sector 2 & 2nd spinner - Sector 1
1st spinner - Sector 2 & 2nd spinner - Sector 2
1st spinner - Sector 3 & 2nd spinner - Sector 1
1st spinner - Sector 3 & 2nd spinner - Sector 2
1st spinner - Sector 4 & 2nd spinner - Sector 1

Out of these seven outcomes, only four have a sum less than five, which are:

1st spinner - Sector 1 & 2nd spinner - Sector 1
1st spinner - Sector 1 & 2nd spinner - Sector 2
1st spinner - Sector 2 & 2nd spinner - Sector 1
1st spinner - Sector 3 & 2nd spinner - Sector 1

So, the probability of getting a sum less than five is 4 out of 7.

Hence, the probability is 4/7.

Hope that spins you right round with humor!

To find the probability that the sum of both scores is less than five, we need to consider all the possible outcomes and determine how many of them satisfy the condition.

Let's start by listing all the possible outcomes when spinning each spinner once. Since each spinner has four sectors, there are a total of 4 x 4 = 16 possible outcomes. We can represent these outcomes in a two-dimensional table as follows:

| Spinner 1 | Spinner 2 |
|--------------|--------------|
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 1 | 4 |
| 2 | 1 |
| 2 | 2 |
| 2 | 3 |
| 2 | 4 |
| 3 | 1 |
| 3 | 2 |
| 3 | 3 |
| 3 | 4 |
| 4 | 1 |
| 4 | 2 |
| 4 | 3 |
| 4 | 4 |

Now, let's determine which outcomes have a sum less than five:

| Spinner 1 | Spinner 2 |
|--------------|--------------|
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 2 | 1 |
| 2 | 2 |
| 3 | 1 |

Out of the 16 possible outcomes, only 6 of them satisfy the condition.

Therefore, the probability that the sum of both scores is less than five is 6/16, which can be simplified to 3/8.

So the final answer is 3/8.