Salts of barium, barium sulfate Particularly, When applied orally and because of its low solubility (Ksp = 1 x 10 ^ -10) Increase contrast for X-rays in medical diagnosis of the digestive system. Considering que Were reacted 7 × 10 -5 moles of CaCl2 with an equivalent amount of Na2SO4 in sufficient distilled water to make 1000 mL, calculate the mass of BaSO4 produces, the precipitate is filtered and dried

Your question is about as clear as mud. You should learn how to ask a question. I assume, put into plain English, you have 7E-5 mols CaCl2 and 7E-5 mols Na2SO4, how much BaSO4 is produced. The answer is none. You can't produce BaSO4 unless barium ion is reacted with a sulfate. You may have meant BaCl2 instead of CaCl2.

Barium salts, especially the barium sulphate, when applied by the oral route and due to its low solubility (Kps = 1 × 10E-10), increase the contrast to the X-ray, in medical diagnosis of the digestive system. Considering that were-reacted 7 × 10E-5 moles BaCℓ2 with equivalent amount of Na2SO4) in distilled water enough to make up to 1000 mL, calculate the mass of BaSO4 produced, if the precipitate is filtered and dried

Im so sorry

To calculate the mass of BaSO4 produced, we need to determine the limiting reagent in the reaction. The limiting reagent is the reactant that is completely consumed, and it determines the maximum amount of product that can be formed.

First, let's calculate the moles of BaSO4 produced from the given moles of CaCl2.

Given:
Moles of CaCl2 = 7 × 10^(-5) moles

The balanced chemical equation for the reaction is:
CaCl2 + Na2SO4 → CaSO4 + 2NaCl

From the balanced equation, we can see that the stoichiometric ratio between CaCl2 and BaSO4 is 1:1. This means that one mole of CaCl2 will produce one mole of BaSO4.

Therefore, the moles of BaSO4 produced would be equal to the moles of CaCl2, which is 7 × 10^(-5) moles.

Now, let's calculate the mass of BaSO4 produced using the molar mass of BaSO4.

The molar mass of BaSO4 can be calculated as follows:
Molar mass of Ba = atomic mass of Ba = 137.33 g/mol
Molar mass of S = atomic mass of S = 32.07 g/mol
4 × (molar mass of O) = 4 × 16.00 g/mol = 64.00 g/mol

Therefore, the molar mass of BaSO4 = (137.33 + 32.07 + 64.00) g/mol = 233.40 g/mol

Now, let's calculate the mass of BaSO4:
Mass of BaSO4 = moles of BaSO4 × molar mass of BaSO4
= 7 × 10^(-5) moles × 233.40 g/mol
= 0.01634 g

Therefore, the mass of BaSO4 produced is approximately 0.01634 grams.

Note: It's important to remember that this calculation assumes the reaction goes to completion and that there are no other factors affecting the reaction such as impurities or side reactions.