If 6.00g of carbon is heated in air, the mass of the product obtained could either be 22.0g or 14.6g depending on the amount of air present. Using calculations with what law will this be in accordance?

Proust's law or the law of definite composition.

6 gram C is 1/2 mole, the remaining 16 gram is 1 mole O, yielding 1/2 mole of CO2.

6 gram C is 1/2 mole, the remaining 8.6 g represents CO. I suspect there is a typo error here, instead of 14.6 it should have been 14.0

Pls explain

This will be in accordance with the Law of Conservation of Mass.

To determine the law that governs this situation, we need to analyze the given information. We know that when 6.00g of carbon is heated in air, the mass of the product obtained can be either 22.0g or 14.6g, depending on the amount of air present.

Based on this information, we can conclude that this situation is in accordance with the Law of Definite Proportions, also known as the Law of Constant Composition.

According to the Law of Definite Proportions, a given compound always contains the same elements in the same proportion by mass. In other words, regardless of the amount of carbon or air present, the ratio of the masses of carbon and oxygen in the product will always be the same.

In this case, when 6.00g of carbon is heated in air, the product obtained can either be 22.0g or 14.6g. These two different masses indicate that the ratio of the masses of carbon and oxygen in the product varies depending on the amount of air present.

Therefore, the situation described is in accordance with the Law of Definite Proportions.