Then air exerts a forward force of 8 N on the
propeller of a 0.25 kg model airplane.
If the plane accelerates forward at 1.8 m/s^2,
what is the magnitude of the resistive force
exerted by the air on the airplane?
Answer in units of N.
net force=mass*a
forwardforce-resistiveforce=ma
8-resistiveforce=.25*1.8
solve for resistive force.
Then air exerts a forward force of 8 N on the
propeller of a 0.25 kg model airplane.
If the plane accelerates forward at 1.5 m/s
2
,
what is the magnitude of the resistive force
exerted by the air on the airplane?
Answer in units of N.
To find the magnitude of the resistive force exerted by the air on the airplane, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. Mathematically, it can be written as:
Net force = mass × acceleration
In this case, the net force acting on the airplane is the difference between the forward force exerted by the air on the propeller and the resistive force exerted by the air on the airplane.
Net force = Forward force - Resistive force
Since the forward force is given as 8 N and the acceleration is given as 1.8 m/s^2, we can substitute these values into the equation:
8 N - Resistive force = 0.25 kg × 1.8 m/s^2
Now, we can solve for the resistive force:
Resistive force = 8 N - (0.25 kg × 1.8 m/s^2)
Resistive force = 8 N - 0.45 N
Resistive force = 7.55 N
Therefore, the magnitude of the resistive force exerted by the air on the airplane is 7.55 N.