List five numbers that have 3,5,7 as prime factor
5 * 3 * 7 = ?
5 * 3 * 7 * 2 = ?
Continue on.
To find five numbers that have 3, 5, and 7 as prime factors, we can start by finding the smallest number that has all three prime factors and continue to find the subsequent numbers.
1. Smallest number: 3 x 5 x 7 = 105
2. Next number: 2 x 3 x 5 x 7 = 210
3. Next number: 3 x 3 x 5 x 7 = 315
4. Next number: 2 x 2 x 3 x 5 x 7 = 420
5. Next number: 3 x 3 x 3 x 5 x 7 = 945
So, the five numbers that have 3, 5, and 7 as prime factors are: 105, 210, 315, 420, and 945.
To list five numbers that have 3, 5, and 7 as prime factors, we need to find numbers that are multiples of these prime numbers. Here's how you can find these numbers:
1. Start by listing the prime factors:
- 3 is a prime factor, so any number should be divisible by 3.
- 5 is a prime factor, so any number should be divisible by 5.
- 7 is a prime factor, so any number should be divisible by 7.
2. Now, we can generate five numbers that satisfy the above conditions:
- The first number is 3 * 5 * 7 = 105.
- The second number is 2 * 3 * 5 * 7 = 210 (any other prime factor can be included).
- The third number is 3^2 * 5 * 7 = 315.
- The fourth number is 3 * 5^2 * 7 = 525.
- The fifth number is 3 * 5 * 7^2 = 1029.
So, the five numbers that have 3, 5, and 7 as prime factors are 105, 210, 315, 525, and 1029.