The graph at the right is a positive vs. Time graph for the motion of an object moving along a horizontal (x) axis For each of the 8 1-second time intervals, describe the displacement, instantaneous velocity (+/- and whether the velocity is increasing or decreasing) and the instantaneous acceleration of the object (+/-) for that individual 1-second time interval. Note that these descriptions can change inside of each of the time intervals ( i.e. during a single interval, the velocity may start off constant, but could change in the middle of that 1-second interval).
Since I can't get a visual represenation to send, I'll describe it so you can draw it to see:
Position Vs. Time graph (8x8) grid!
Position (y axis) ... x(m)
Starts at 0, count by 20's to reach 80 at the very top line on the 8x8 grid.
Time (x axis) ... t(s)
Starts at 0, count by 1 s all the way to 8 s (which should be on the very last line of the 8x8 grid.
PLEASE TELL ME IF YOU CAN'T VISUALLY DRAW THE GRAPH SO I CAN EXPLAIN IT BETTER OR DESCRIBE IT BETTER. I TRIED MY BEST TO DESCRIBE THE GRAPH FOR YOU TO HELP ME. Thankyou!
Now here are the points on the graph:
1.) From 0-1 second, the line is constant at 43m.
2.) From 1-2 seconds, the line is a positive slight under curve from 43m to point (2,60).
3.) From 2-3 seconds, the point goes from (2s, 60m) to (3s, 70m) at a positive slight over curve(slowing down but still positive).
4.) From 3-4 seconds, the line is constant from (3,70) to (4,70).
5.) From 4-5 seconds, the line is slightly decreasing from point (4,70) to points (5,68).
6.) From 5-6 seconds, starts from point (5,68) and decreases at a straight diagonal line to (6s, 2m).
7.) From 6-7 seconds, starting from point (6s, 2m), going to points (7,10) at a diagonal line but half the box, curved.
8.) From 7-8 seconds, the line is constant and ends at (8s, 10m)
HOPEFULLY, YOU CAN UNDERSTAND AND DRAW THAT. I TRIED TO DESCRIBE THE POINTS AND LINES OF WHERE IT IS GOING.
________________________________________
Now fill in the chart of the intervals describing its specific VELOCITY at that time during how many meters, and the ACCELERATION!
* I had to describe the position of each interval. I got all those right but the velocity column and acceleration column, I really need help.
______________________________________ |Describe Velocity| & separately |Describe Acc.| for each intervals!
INTERVALS (seconds)
1s
2s
3s
4s
5s
6s
7s
8s
time is ending at t time
eg = 1 sec is ending at 1, first second
v is average velocity in inteval
(final-original)
a is acceleration change in speed/1 second
CHECK MY WORK
___ v a
1s 00 00
2s 17 10 v=(60-43) a =(v3-0)=10
3s 10 -17
4s 00 -2
5s -2 (2m-66)
6s (2m-68) -58
7s (10-2m) (2m -10)
8s 00 (10-2m)
everything is divided by one second
for velocity I take position
at n minus position at (n-1)
for acceleration I take velocity during n+1 - velocity during n
By the way I am assuming that your curve is continuous and smooth.
If there is an instantaneous change in slope (velocity), for example at 1 second, then the acceleration is infinite. a = (V2-V1)/0
CHECK MY WORK
___ v a
1s 00 00
2s 17 10 v=(60-43) a =(v3-0)=10
3s 10 -17
4s 00 -2
5s -2 (2m-66)
6s (2m-68) -58
7s (10-2m) (2m -10)
8s 00 (10-2m)
I got lost with the numbers. Could you please explain in words.. I am still lost. Hopefully I get a reply before 11 am so I can process the info before 12. Thanks Mr.Damon
Would be a major Extreme Help. any explanations and descriptions will do for each interval. 2 hours looking at this question
I do not visualize what the graph shows.
Perhaps this will help you.http://dev.physicslab.org/Document.aspx?doctype=5&filename=Kinematics_ConstantVelocityPositionTimeGraphs2.xml
I can not do much more
velocity=Vn = (Xn - Xn-1)/1 second
acceleration = (Vn-Vn-1)/1 second
Sure! Let's break it down interval by interval:
1s: For the first second, the displacement is 43m (since the line is constant). The instantaneous velocity is 0m/s since the position does not change. The instantaneous acceleration is also 0m/s^2 since the velocity is constant.
2s: From 1-2 seconds, the displacement is 17m (60m - 43m). The instantaneous velocity is 17m/s since the position changes by 17m in 1 second. The instantaneous acceleration is 10m/s^2 since the velocity changes by 17m/s in 1 second.
3s: From 2-3 seconds, the displacement is 10m (70m - 60m). The instantaneous velocity is -10m/s since the position changes by -10m in 1 second (velocity can be negative if the object is moving in the opposite direction). The instantaneous acceleration is -17m/s^2 since the velocity changes by -10m/s in 1 second.
4s: For the fourth second, the displacement is 0m since the position does not change (70m - 70m). The instantaneous velocity is 0m/s since the position does not change. The instantaneous acceleration is -2m/s^2 since the velocity changes by -10m/s in 1 second.
5s: From 4-5 seconds, the displacement is -2m (68m - 70m). The instantaneous velocity is -2m/s since the position changes by -2m in 1 second. The instantaneous acceleration is -2m/s^2 since the velocity changes by -2m/s in 1 second.
6s: From 5-6 seconds, the displacement is -66m (2m - 68m). The instantaneous velocity is -66m/s since the position changes by -66m in 1 second. The instantaneous acceleration is -58m/s^2 since the velocity changes by -66m/s in 1 second.
7s: From 6-7 seconds, the displacement is 8m (10m - 2m). The instantaneous velocity is 8m/s since the position changes by 8m in 1 second. The instantaneous acceleration is -8m/s^2 since the velocity changes by -8m/s in 1 second.
8s: For the eighth second, the displacement is 0m since the position does not change (10m - 10m). The instantaneous velocity is 0m/s since the position does not change. The instantaneous acceleration is -8m/s^2 since the velocity changes by -8m/s in 1 second.
I hope this clarifies the descriptions for you. Let me know if you need any further assistance!