Solve for d
D(t)= -8cos (pi(t)/30)+8
solve what? d is just the definition of a function.
i mean the y value,change it to sin function
To solve for d, we need to isolate the variable d in the given equation D(t) = -8cos(pi(t)/30) + 8.
Here's how you can do it step-by-step:
1. Start with the equation: D(t) = -8cos(pi(t)/30) + 8.
2. Subtract 8 from both sides of the equation to isolate the cosine term: D(t) - 8 = -8cos(pi(t)/30).
3. Divide both sides of the equation by -8 to isolate the cosine term: (D(t) - 8)/-8 = cos(pi(t)/30).
4. Take the inverse cosine (arccos) of both sides of the equation to remove the cosine: arccos((D(t) - 8)/-8) = pi(t)/30.
5. Multiply both sides of the equation by 30/pi to isolate the variable t: (30/pi) * arccos((D(t) - 8)/-8) = t.
6. Now, we have the equation t = (30/pi) * arccos((D(t) - 8)/-8) as an expression for t.
Thus, to solve for d, you will need to substitute the desired values of t into the equation t = (30/pi) * arccos((D(t) - 8)/-8), and then evaluate it.