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You have a total of 21 pens and pencils. You have 3 more pens than pencils. Write a system of linear equations that represent this situation. How many of each do you have?

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  1. pens--- x
    pencils --y
    x+y = 21

    x = y+3

    I just translated the English to Math

    solve

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  2. Let p = number of pencils
    Therefore pens = p + 3

    P + (p+3) = 21
    2p + 3 = 21

    Then solve for p

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