What is the solution of the system? use substitution . 4x+2y=10, y=-3x+6

@steve can you help??

It tells you to use substitution and you already have y, all alone on the left. It is (-3x+6)

so
use that. substitute it for x i the other (first) equation

4 x + 2(-3x+6) = 10

4 x - 6 x + 12 = 10

2 x = 2

x = 1

y = -3(1) + 6 = 3

My answer chosies are

a. (1,-3)
b.(1,3)
c.(3/10, 4/5)
d.(-2,-2)
Is it b? @damon

To find the solution using substitution, we will substitute the value of y from the second equation into the first equation.

Given:
Equation 1: 4x + 2y = 10
Equation 2: y = -3x + 6

Step 1: Substitute the value of y from Equation 2 into Equation 1.
4x + 2(-3x + 6) = 10

Step 2: Simplify the equation by distributing the 2 to both terms inside the parentheses.
4x - 6x + 12 = 10

Step 3: Combine like terms.
-2x + 12 = 10

Step 4: Move the constant term to the other side of the equation.
-2x = 10 - 12
-2x = -2

Step 5: Divide both sides by -2 to solve for x.
x = -2 / -2
x = 1

Now, substitute the value of x back into Equation 2 to find the value of y.

Equation 2: y = -3x + 6
y = -3(1) + 6
y = -3 + 6
y = 3

Therefore, the solution to the system of equations is x = 1 and y = 3.