Question

If x and y satisfy the equation (x+5)^2+(y-12)^2=14

then find the minimum value (x^2+y^2) plz help show working

Answer 1

The equation is a circle with radius √14, centered at (-5,12)

So, the minimum value of x^2+y^2 is the point on the circle nearest the origin.

Since the center of the circle is 13 units away, the closest point on the circle is 13-√14 units away.