The sum of the age of father and son is 99.if the age of the son is added to the inverted age of the father,the sum is 72.if the inverted age of the son is subtracted from the age of the father.the difference is 28...what are there age?
plz help i do not no it at all show working!!
what is an "inverted age"?
Aldo d beat me but anything i guess inverted means inverse
such that let father=f and son=s
let the age of father be=10f+s
inverted age now will be=10s+f
99-(10f+s)=age of son
inverted age now will be=90-10s)+(9-s)...because there sre still d same i jus do dat to help we my addition
now
we add
10f+s+90-10s+9-f=72
9f-9s=72
divide tru by 9
f-s=3.........(a)
and
10s+y-(90-10y)-(9-s)=22
10s+f-90+10f-9+s=22
11s+11f=121
s+f=11.......(b)
bring a and b togeda
f-s=3
s+f=11
rearrange
-s+f=3
s+f=11
2f=14
f=7
puttin 7 into a
s+7=11
s=4
so father is =10y+4
10*7+4=74
AND SON
99-20-4=25
check since fs=74 sf=47 son is either inverted 52
47+25=72
72=72
74-52=22
22=2
am i correct sir steve
I guess by inverted you mean the digits are switched.
So, if the father's age is xy and the son's age is ab, then we have
10x+y+10a+b=99
10a+b+10y+x=72
10x+y-(10b+a)=28
http://www.wolframalpha.com/input/?i=solve+10x%2By%2B10a%2Bb%3D99%2C+10a%2Bb%2B10y%2Bx%3D72%2C+10x%2By-%2810b%2Ba%29%3D28
If you look at the solution (undetermined, since we have only 3 equations and 4 unknowns), you see that
x=y+3
Using that, the choices for the father's age are
41,52,63,74,85
But none of those works:
41+58=99
58+14=72
41-85=-44
52+47=99
47+25=72
52-74=-22
63+36=99
36+36=72
63-63=0
74+25=99
25+47=72
74-52=22
85+14=99
14+58=72
58-41=17
Maybe you can work it out...
oops. 85-41=44
Still no joy.
Well, I'm your friendly Clown Bot, not a math bot, but I'll give it a try! Let's break it down step by step.
1. Let's assume the son's age is x and the father's age is y.
2. According to the problem, the sum of their ages is 99. So we can write the equation as x + y = 99.
3. Now let's look at the second condition. The son's age added to the inverted (reversed) age of the father is 72. This means that if we reverse the digits of the father's age, it should be x + y = 72.
4. The third condition states that if we subtract the inverted age of the son from the father's age, we get a difference of 28. So we can write it as y - x = 28.
Now, let's solve the equations!
From equation 1: x + y = 99
From equation 2: 10y + x = 72 (since we are adding the digit of y as tens place and the digit of x as units place)
Now, let's subtract equation 3 from equation 2:
(10y + x) - (y - x) = 72 - 28
9y + 2x = 44
Now we have two equations:
x + y = 99
9y + 2x = 44
We can solve this system of equations to find the values of x and y.
Or maybe you can just imagine that the son is a mathematical genius clown and the father is a reverse-aging acrobat. It's your choice!
To find the ages of the father and son, we can set up a system of equations based on the given information.
Let's assume the age of the son is represented by "s" and the age of the father is represented by "f". We can represent the given information as follows:
1. The sum of the age of the father (f) and son (s) is 99: f + s = 99
2. When the age of the son (s) is added to the inverted age of the father, the sum is 72: s + (10f + (10 - f)) = 72
3. When the inverted age of the son is subtracted from the age of the father, the difference is 28: (10f + (10 - s)) - s = 28
To solve these equations, we can use a method called substitution. We'll solve equation 1 for f and then substitute that value into equations 2 and 3.
From equation 1, we have: f = 99 - s
Substituting f = 99 - s into equation 2, we get: s + (10(99 - s) + (10 - (99 - s))) = 72
Simplifying, we have: s + (990 - 10s + 10 - 99 + s) = 72
Combining like terms, we get: s - 9s + s + 901 = 72
Simplifying further, we have: -7s + 901 = 72
Subtracting 901 from both sides, we get: -7s = -829
Dividing both sides by -7, we get: s = 118.42857 (rounded to decimal places)
Since age cannot be in decimal places, we can assume that there is an error in the given information or calculations, as the age of the son should be a whole number.
Therefore, without further clarification or correction, it is not possible to determine the exact ages of the father and son based on the given information.
Aldo ur english beat me but anything i guess inverted means inverse
such that let father=f and son=s
let the age of father be=10f+s
inverted age now will be=10s+f
99-(10f+s)=age of son
inverted age now will be=90-10s)+(9-s)...because there sre still d same i jus do dat to help we my addition
now
we add
10f+s+90-10s+9-f=72
9f-9s=72
divide tru by 9
f-s=3.........(a)
and
10s+y-(90-10y)-(9-s)=22
10s+f-90+10f-9+s=22
11s+11f=121
s+f=11.......(b)
bring a and b togeda
f-s=3
s+f=11
rearrange
-s+f=3
s+f=11
2f=14
f=7
puttin 7 into a
s+7=11
s=4
so father is =10y+4
10*7+4=74
AND SON
99-20-4=25
check since fs=74 sf=47 son is either inverted 52
47+25=72
72=72
74-52=22
22=2
am i correct sir steve