I really need help and no offense but I would prefer Dr.Bob or Writeacher or somebody that knows what they're doing. Where are they?
okay well i'm not a teacher but i will try to help if i can. i'm a tutor if that gives you any confidence
Okay, how do you find the equation of the tangent line at the point (2,81). The derived function is: 4((4x^2-8x+3)^3) * (8x-8)
Thank u
Elise, are you there?
Yikes! sorry i can do that level but i don't feel confident enough to give you help that wouldn't confuse you. all i can say is don forget the definition of a derivative.
yeah i just responded. i was getting my computer back. sorry kid wish i could help but i'd hate to get you confused. look at my last response.
At 12:24 am??? We're sleeping!!
That's 12:24 Eastern time, 11:24 Central time, 10:24 Mountain time, and 9:24 Pacific time.
The teachers I know live in Eastern or Central time.
=)
Thank you for using the Jiskha Homework Help Forum. Our first suggestion to you is not to procrastinate. Plan ahead so teachers have time to answer for you. In addition be sure to list the SUBJECT matter: such as Math, Physics, Biology, Science, etc. We are busy and most of only look at the ones labeled in our area! I for one am not going to guess at the problem.
One last comment? First, thanks for using Jiskha. Second, thanks for the compliment. Third, I love doing this BUT sometimes grocery shopping, doctor's appointments, getting my car to the garage for mechanical work, etc must be done. With regard to today when you posted this note, I took myself and a friend out to eat to celebrate my birthday. Had a great time. So OUT is where I was.
I understand that you would prefer help from someone like Dr. Bob or Writeacher, but unfortunately, I am an AI bot and they are not currently available on this platform. However, I will do my best to assist you with your question.
To find the equation of the tangent line at the point (2,81) using the given derived function, you first need to find the slope of the tangent line. The slope of the tangent line at any point on a curve is given by the derivative of the function at that point. In this case, the given derived function is 4((4x^2-8x+3)^3) * (8x-8).
To find the derivative, apply the chain rule to each term in the function and simplify. The derivative will be the slope of the tangent line at any point on the curve.
Once you have the derivative, substitute the x-coordinate of the given point (2) into it to find the slope at that point. This will give you the slope of the tangent line.
Next, you can use the point-slope form of a linear equation to find the equation of the tangent line. The point-slope form is y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope you found in the previous step.
Substitute the values of the point (2,81) and the slope into the point-slope form, and simplify the equation to get the equation of the tangent line.
I hope this helps! If you have any further questions, feel free to ask.