a 4200 kg helicopter accelerate upward 3m/s^2. lift force is exerted by the air on the propellers?(g=10m/s^2)
well, F = ma = 4200(3 + 10)
54600N
To calculate the lift force exerted by the air on the propellers of the helicopter, we need to first understand the concept of weight and the relationship between weight and lift force.
Weight is the force exerted by gravity on an object and is calculated as the product of mass and the acceleration due to gravity (g). In this case, the weight of the helicopter can be calculated as follows:
Weight = mass * acceleration due to gravity
= 4200 kg * 10 m/s^2
= 42,000 N
Now, let's consider the acceleration of the helicopter. Since the acceleration is provided as 3 m/s^2 in the upward direction, we need to determine the net force acting on the helicopter.
Net force = mass * acceleration
= 4200 kg * 3 m/s^2
= 12,600 N
For the helicopter to accelerate upward, the net force must be greater than the weight. Therefore, the lift force can be calculated by subtracting the weight from the net force:
Lift force = Net force - Weight
= 12,600 N - 42,000 N
= -29,400 N
The negative sign indicates that the lift force is directed opposite to the weight, which is upward in this case. So, the lift force exerted by the air on the propellers of the helicopter is 29,400 N upwards.