What is the mass of water required to fill a circular hot tub 3.4 m in diameter and 1.4 m deep?

Answer in units of kg.

I got 0.2669 but wrong also

Ignoring you silly and meaningless school subject of

diameter/kg

volume = πr^2 h
= π(1.7)^2 (1.4) m^3

= 1000π(1.7)^2 (1.4) kg, (assuming 1 m^3 = appr 1000 kg with certain temperature restrictions)
= ....

To find the mass of water required to fill a hot tub, we need to know the volume of the hot tub and then multiply it by the density of water.

Step 1: Calculate the volume of the hot tub.
The hot tub is in the shape of a cylinder. The formula to calculate the volume of a cylinder is given by V = πr^2h, where V is the volume, r is the radius, and h is the height (or depth) of the cylinder.

Given:
Diameter of the hot tub = 3.4 m
Radius (r) = Diameter/2 = 3.4 m / 2 = 1.7 m
Height (h) = 1.4 m

Using the formula for volume of a cylinder:
V = πr^2h
V = π * (1.7 m)^2 * 1.4 m
V ≈ 12.397 m^3 (applying the value of π as approximately 3.14)

Step 2: Multiply the volume by the density of water.
The density of water is approximately 1000 kg/m^3.

Mass = Volume * Density
Mass = 12.397 m^3 * 1000 kg/m^3
Mass ≈ 12,397 kg

Therefore, the mass of water required to fill the circular hot tub is approximately 12,397 kg.