Find the value of x so that the line passes through the points (2,3) and (x,9) and has a slope of 3/2. I'm clueless!
Just use your definition of slope, calculate it, then set it equal to 3/2
(9-3)/(x-2) = 3/2
6/(x-2) = 3/2
3x - 6 = 12
3x = 18
x = 6
whoever this tutor is sucks
To find the value of x that satisfies the given conditions, we need to use the slope formula:
slope = (change in y) / (change in x)
In this case, the slope is given as 3/2, and we have the point (2,3) and another point (x,9).
Using the slope formula, we can calculate the change in y and change in x:
(3/2) = (9 - 3) / (x - 2)
Simplifying this equation, we have:
3/2 = 6 / (x - 2)
Cross-multiplying, we get:
3(x - 2) = 2 * 6
Expand and solve for x:
3x - 6 = 12
Adding 6 to both sides, we get:
3x = 18
Dividing both sides by 3, we find:
x = 6
So, the value of x that satisfies the given conditions is 6.
What do I do to from line 2 to line 3? How did you get 3x- 6=12?
Can you break it down, line by line?not following
line 2 to 3?
multiply line 2, each side by 2(x-2)
2(x-2)*6/(x-2)=2(x-2)*3/2
12=3x-6