Makoto and his friends rolled two fair number cubes 500 times and recorded the sum of the numbers shown on the cubes each time.On 42 of the trials the sum was 10.Which of these is most likely the probability that the sum of the numbers shown on the cubes is 10 when two fair number cubes are rolled?

To find the probability of the sum being 10 when two fair number cubes are rolled, we need to compare the number of successful outcomes (sums of 10) to the total number of possible outcomes.

Given that Makoto and his friends rolled the two number cubes 500 times, and on 42 of those trials the sum was 10, we can calculate the probability as follows:

Probability = Number of successful outcomes / Total number of possible outcomes

Number of successful outcomes = 42 (as mentioned in the question)

Total number of possible outcomes = 500 (as mentioned in the question)

Now, let's calculate the probability:

Probability = 42 / 500

Simplifying the fraction by dividing both the numerator and denominator by the greatest common divisor (GCD), we get:

Probability = 21 / 250

Therefore, the most likely probability that the sum of the numbers shown on the cubes is 10 when two fair number cubes are rolled is 21/250.

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