If an TV is 51 inches wide and the height is half the size of the width, what is its screen size to the nearest inch?
I assume you're looking for the diagonal, the hypotenuse of this right triangle.
a^2 + b^2 = c^2
51^2 + 25.5^2 = c^2
2601 + 650.25 = c^2
3,251.25 = c^2
57 = c
thanks madam
You're welcome, sir.
To find the screen size of the TV, you need to calculate the diagonal measurement using the width and height. The diagonal measurement represents the screen size in inches.
Given that the width of the TV is 51 inches, and the height is half the width, we can first find the height by dividing the width by 2.
Height = Width/2
Height = 51 inches/2
Height = 25.5 inches
Now, to find the diagonal measurement, we can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the other two sides (width and height). In this case, the width and height form the two sides of a right triangle, with the diagonal being the hypotenuse.
Diagonal^2 = Width^2 + Height^2
Substituting the known values:
Diagonal^2 = 51 inches^2 + 25.5 inches^2
Diagonal^2 = 2601 inches^2 + 650.25 inches^2
Diagonal^2 = 3251.25 inches^2
Now, to find the diagonal, we take the square root of both sides:
Diagonal ≈ √3251.25 inches^2
Diagonal ≈ 57.03 inches
Therefore, to the nearest inch, the screen size of the TV is approximately 57 inches.