A circular path 2 feet wide has a an inner diameter of 150 feet. How much farther is it around the outer edge of the path than around the inner edge?
THX!
Umm... Aren't you supposed to show the work cause I ain't see any good work.
pi = http://cdn.phys.org/newman/gfx/news/hires/pi.jpg
and
http://www.google.com/?gws_rd=ssl#q=pi
pie = http://www.google.com/imgres?imgurl=http://www.chowstatic.com/assets/recipe_photos/10844_tart_cranberry_pie.jpg&imgrefurl=http://www.chowhound.com/pictures/vegetarian-thanksgiving-menu/tart-cranberry-pie&h=2000&w=3000&tbnid=LVJeKIJsxns2bM:&docid=wGZP90dp8J05ZM&ei=CCeBVoPRLMjHmQHA1Kf4AQ&tbm=isch&ved=0ahUKEwiD9fOuw_7JAhXIYyYKHUDqCR8QMwg3KAUwBQ
(154 x 3.14)-(150 x 3.14)=
483.56-471=12.56
(rounded answer 12.5)
Enjoy!
poopie
To find the difference in distance between the outer edge and the inner edge of the circular path, we need to determine the lengths of both edges separately.
First, let's calculate the circumference of the outer edge of the path. The circumference of a circle can be found using the formula C = πd, where C is the circumference and d is the diameter.
Given that the inner diameter of the circular path is 150 feet, the outer diameter (including the path width) would be 150 feet + 2 feet (width on both sides) + 2 feet (width on both sides) = 154 feet.
Therefore, the circumference of the outer edge is C = π × 154 = 484 feet (approximately).
Next, let's calculate the circumference of the inner edge of the path. The inner diameter is already given as 150 feet, so the circumference of the inner edge is C = π × 150 = 471 feet (approximately).
To determine how much farther it is around the outer edge compared to the inner edge, we subtract the circumference of the inner edge from the circumference of the outer edge:
484 feet (outer edge) - 471 feet (inner edge) = 13 feet.
So, it is approximately 13 feet farther around the outer edge of the path than around the inner edge.
2x pie x r2 - 2x pie x r1
2x 22/7 x 77 - 2 x 22/7 x 75
= 12.5 feet