area (triangle BCE )=75.2 meter square. Find area ( ABCD) where ABCD is a parallelogram
the triangle and the ||gram have the same height and base
so the ||gm = 2(75.2) = 150.4 m^2
To find the area of parallelogram ABCD, we need to use the fact that the area of a triangle is half the product of its base and height.
1. First, let's determine the base and height of triangle BCE:
Since BCE is a triangle within parallelogram ABCD, its base will be the same as one side of the parallelogram. Let's call this side length 'b'.
The height of triangle BCE can be obtained by drawing a perpendicular line from point B to side CE of the parallelogram. Let's call this height 'h'.
2. Since the area of triangle BCE is given as 75.2 square meters, we can use the formula for the area of a triangle to determine the values of 'b' and 'h':
Area of triangle BCE = (1/2) * base * height
75.2 = (1/2) * b * h
3. Now, let's find the area of parallelogram ABCD:
The area of a parallelogram is equal to the product of base and height. Since triangle BCE is half the area of parallelogram ABCD, we can double the area of triangle BCE to find the area of the parallelogram.
Area of ABCD = 2 * Area of BCE
= 2 * 75.2
= 150.4 square meters
Therefore, the area of parallelogram ABCD is 150.4 square meters.