Two resistors 3 Ω and 6 Ω are connected in parallel across a 6 V battery. What is the current flow through the 3 Ω resistor?
6 A
3 A
4 A
2 A
2 man!
To determine the current flow through the 3 Ω resistor, we can use Ohm's Law. In a parallel circuit, the voltage across each resistor is the same.
Given:
Resistance of the 3 Ω resistor = 3 Ω
Resistance of the 6 Ω resistor = 6 Ω
Voltage across the resistors = 6 V
To find the current flowing through the 3 Ω resistor, we can use the formula:
I = V/R
where I is the current, V is the voltage, and R is the resistance.
For the 3 Ω resistor:
I = 6 V / 3 Ω = 2 A
Therefore, the current flowing through the 3 Ω resistor is 2 A.
To find the current flow through the 3 Ω resistor, we can use Ohm's Law. Ohm's Law states that the current (I) flowing through a component is equal to the voltage (V) across the component divided by the resistance (R) of the component.
In this case, the voltage across the resistors is 6 V and the resistance of the 3 Ω resistor is 3 Ω. Therefore, we can calculate the current flowing through the 3 Ω resistor using the formula:
I = V / R
I = 6 V / 3 Ω
I = 2 A
So, the current flowing through the 3 Ω resistor is 2 A.
i = V/R = 6/3 = 2 amps
in parallel, currents add
in series, voltages add