Two resistors 3 Ω and 6 Ω are connected in parallel across a 6 V battery. What is the current flow through the 3 Ω resistor?



6 A

3 A

4 A

2 A

2 man!

To determine the current flow through the 3 Ω resistor, we can use Ohm's Law. In a parallel circuit, the voltage across each resistor is the same.

Given:
Resistance of the 3 Ω resistor = 3 Ω
Resistance of the 6 Ω resistor = 6 Ω
Voltage across the resistors = 6 V

To find the current flowing through the 3 Ω resistor, we can use the formula:

I = V/R

where I is the current, V is the voltage, and R is the resistance.

For the 3 Ω resistor:
I = 6 V / 3 Ω = 2 A

Therefore, the current flowing through the 3 Ω resistor is 2 A.

To find the current flow through the 3 Ω resistor, we can use Ohm's Law. Ohm's Law states that the current (I) flowing through a component is equal to the voltage (V) across the component divided by the resistance (R) of the component.

In this case, the voltage across the resistors is 6 V and the resistance of the 3 Ω resistor is 3 Ω. Therefore, we can calculate the current flowing through the 3 Ω resistor using the formula:

I = V / R

I = 6 V / 3 Ω

I = 2 A

So, the current flowing through the 3 Ω resistor is 2 A.

i = V/R = 6/3 = 2 amps

in parallel, currents add
in series, voltages add