Solve the following system of equations:
x − 2y = 6
2x − 4y = 10
Infinitely many solutions
No solutions
(0, 0)
(6, 10)
is it A
x − 2y = 6
2x − 4y = 10
x = 2y + 6
2(2y + 6) - 4y = 10
4y + 12 - 4y = 10
Yes, A is right.
Yay thanks
You're welcome.
y = x/2 -3
and
y = x/2 -5
two parallel lines with the same slope but different y axis intercepts
therefore
they never, ever, cross
and
there is no solution
so is it a or b
I guess you will have to check your text book :)
Damon u were right!! [= (=
whew, you had me worried there.
To solve the system of equations, we can use the method of substitution or elimination. Let's use the method of elimination.
Given equations:
x - 2y = 6 ---(1)
2x - 4y = 10 ---(2)
We want to eliminate one variable, either x or y, so that we can solve for the other variable. We can see that if we multiply equation (1) by 2, we can eliminate x when we subtract equation (2) from it:
2(x - 2y) = 2(6)
2x - 4y = 12 ---(3)
Now, subtracting equation (2) from equation (3):
(2x - 4y) - (2x - 4y) = 12 - 10
0 = 2
This means 0 = 2, which is not true. This implies that the system of equations has no solutions. So, the answer is B - No solutions.