a spring of force constant 1500N/m is acted upon Hy a constant force of 75N .calculate the potential energy stored in the spring
d = 75N * 1m/1500N = 0.05 m.
PE=0.5F * d = 0.5*75 * 0.05 = 1.875 J.
SIMPLE
I DONT UNDERSTAND?
I don't understand where did 0.5 come from
tell me where the 0.5 came from pls right away
To calculate the potential energy stored in a spring, you need to know its force constant and the displacement from its equilibrium position.
The potential energy stored in a spring is given by the formula:
Potential Energy = (1/2) * force constant * (displacement)^2
In this case, the force constant is given as 1500 N/m, and the constant force acting on the spring is 75 N. To calculate the displacement, we can use Hooke's law, which states that the force exerted on a spring is proportional to the displacement from its equilibrium position:
Force = force constant * displacement
Plugging in the values we have:
75 N = 1500 N/m * displacement
Rearranging the equation to solve for displacement:
displacement = 75 N / 1500 N/m
displacement = 0.05 m
Now we have the force constant (1500 N/m) and the displacement (0.05 m). We can plug these values into the formula for potential energy:
Potential Energy = (1/2) * 1500 N/m * (0.05 m)^2
Potential Energy = 3.75 J
Therefore, the potential energy stored in the spring is 3.75 Joules.