The weight of a container completely filled with water is 2.25 kg. The container weighs 0.77 kg when it's 0.2 part is filled with water. Find the weight(in kg) of the container when0.4 part of it is filled with water?
Pls help
let the weight of the container be x kg
let the weight of the water when full be y kg
x + y = 2.25 kg
x + .2y = .77
subtract them
.8y = 1.48 kg
y = 1.85 kg
then x+1.85 = 2.25
x = .4 kg
so x + .4y = .4 + .74 kg = 1.14 kg
Oh, well this is a "weighty" problem! Let's see if I can make it a little lighter for you.
To solve this, we need to find the difference in weight between when the container is completely filled with water and when 0.2 part of it is filled.
The weight of the container when 0.2 part is filled is 0.77 kg. So, we subtract this weight from the weight of the completely filled container:
2.25 kg - 0.77 kg = 1.48 kg
So, the difference in weight between the completely filled container and when 0.2 part is filled is 1.48 kg.
Now, if we want to find the weight of the container when 0.4 part is filled, we can simply add half of the difference in weight:
1.48 kg / 2 = 0.74 kg
And now, we add this to the weight of the completely filled container:
2.25 kg + 0.74 kg = 2.99 kg
So, the weight of the container when 0.4 part is filled with water is approximately 2.99 kg.
I hope that answers your question!
To solve this problem, we can set up a proportion to find the weight of the container when 0.4 parts of it is filled with water.
Let's assume the weight of the container when it is completely empty is W kg.
According to the given information, the weight of the container completely filled with water is 2.25 kg, and the weight of the container when 0.2 part is filled with water is 0.77 kg.
We can set up the following proportion:
(0.2 / 1) = (0.77 / W + 0.77)
(Note: We add the weight of the container when 0.2 part is filled with water to the weight of water to get the weight of container + water)
Now, let's cross-multiply and solve for W:
0.2 * (W + 0.77) = 0.77 * 1
0.2W + 0.154 = 0.77
0.2W = 0.77 - 0.154
0.2W = 0.616
W = 0.616 / 0.2
W = 3.08
Therefore, the weight of the container when 0.4 part of it is filled with water would be:
0.4 * (W + 0.77) = 0.4 * (3.08 + 0.77) = 1.23 + 0.308 = 1.538 kg.
Hence, the weight of the container when 0.4 part of it is filled with water is 1.538 kg.
To find the weight of the container when 0.4 part of it is filled with water, we need to follow these steps:
Step 1: Determine the weight of the container when it is empty.
Given that the weight of the container completely filled with water is 2.25 kg, we subtract the weight of the water to find the weight of the empty container:
Weight of the empty container = 2.25 kg - weight of water
Since 0.2 part of the container is filled with water when it weighs 0.77 kg, we can calculate the weight of water:
Weight of water in 0.2 part of the container = 0.77 kg
Weight of water in the entire container = (0.77 kg) / (0.2 part) x (1 part)
Here, we multiply the weight of water in 0.2 part by the reciprocal of 0.2 to find the weight of water in the entire container.
So,
Weight of water in the entire container = (0.77 kg) / (0.2) = 3.85 kg
Substituting this value in the previous equation, we can calculate the weight of the empty container:
Weight of empty container = 2.25 kg - 3.85 kg = -1.6 kg
Step 2: Calculate the weight of the container when 0.4 part is filled with water.
Now that we have the weight of the empty container, we can calculate the weight of the container when 0.4 part is filled with water.
Weight of the container when 0.4 part is filled with water = Weight of empty container + Weight of water in 0.4 part of the container
Weight of water in 0.4 part of the container = (0.77 kg) / (0.2 part) x (0.4 part)
Here, we multiply the weight of water in 0.2 part by 0.4 to find the weight of water in 0.4 part.
So,
Weight of water in 0.4 part of the container = (0.77 kg) / (0.2) x (0.4) = 1.54 kg
Substituting the known values, we can calculate the weight of the container when 0.4 part is filled with water:
Weight of the container when 0.4 part is filled with water = -1.6 kg + 1.54 kg = -0.06 kg
Therefore, the weight of the container when 0.4 part is filled with water is approximately -0.06 kg.